I am trying to get this code to work without errors and there is one error I cannot get past.
So as long as you have a worksheet named "my_file.csv" then the code works great. It's when I go to open the saved worksheet that I get my first error.![]()
Sub EXPORT_CSV() Dim fPath As String Dim wb0 As Workbook With Application.FileDialog(msoFileDialogFolderPicker) .AllowMultiSelect = False .Show If .SelectedItems.Count > 0 Then fPath = .SelectedItems(1) & "\" Else Exit Sub End If End With fname = fPath & "my_file.csv" Worksheets("my_file.csv").Copy Set wb0 = ActiveWorkbook wb0.SaveAs fname wb0.Close End Sub
The file you are trying to open, 'my_file.csv', is in a different format than specified by the file extension. Verify that the file is not corrupted and is from a trusted source before opening the file. Do you want to open the file now?
And I click yes and the file looks correct; I see the one worksheet with the exact same data on the workbook I saved it from.
Does anyone have any idea what is going on here? Thanks for your help.
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