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YOur way is correct as long as you list all ways. there should be (4/(4-2)!/2!)=4x3/2=6 ways.
If OBA.value=true and OBB.value=true then ....
ab ac ad
bc bd
cd
YOur way is correct as long as you list all ways. there should be (4/(4-2)!/2!)=4x3/2=6 ways.If OBA.value=true and OBB.value=true then ....
ab ac ad
bc bd
cd
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