Hello Guys.
First of all I apologize for my English.
I believe a little background is needed: I have a hush workbook with an inspection template; one of the functionalities is that the user can search employees’ names to assign actions and send notifications emails. I have a worksheet filled with all employees data from GAL and basically I’m interested in two columns: (B) with emails and (D) with names. I have to state that I know very little about VBA but with a lot of help from this forum I came up with a code that search for the employee’s name and place it in a userform listbox for user selection. I recently found out that I have duplicates on names column and that causes me a problem when a subsequent macro has to find the email address associated with this name. After some frustrating attempts to populate a two columns listbox I tried a way around by populating a range in a sheet with the data retrieved by the LOCATE macro but it works sometimes and most of the times don’t. It is a weird thing. I need some help please. Here is the first LOCATE macro and the one I being tried.
Sub Locate(name As String, data As Range)
Dim rngFind As Range
Dim strFirstFind As String
With data
Set rngFind = .Find(name, LookIn:=xlValues, lookat:=xlPart)
If Not rngFind Is Nothing Then
strFirstFind = rngFind.Address
Do
If rngFind.Row > 1 Then
ListBox1.AddItem rngFind.Value
End If
Set rngFind = .FindNext(rngFind)
Loop While Not rngFind Is Nothing And rngFind.Address <> strFirstFind
End If
End With
Set rngFind = Nothing
End Sub
Sub Locate(name As String, data As Range)
Dim rngFind As Range
Dim strFirstFind As String
With data
Set rngFind = .Find(name, LookIn:=xlValues, lookat:=xlPart)
If Not rngFind Is Nothing Then
strFirstFind = rngFind.Address
Do
If rngFind.Row > 1 Then
ThisWorkbook.Sheets("sheet1").Range("AK1").End(xlDown).Offset(1, 0).Value = rngFind.Value
End If
Set rngFind = .FindNext(rngFind)
Loop While Not rngFind Is Nothing And rngFind.Address <> strFirstFind
End If
End With
Set rngFind = Nothing
End Sub
The Variable "name" come from a textbox used by user to input string to search.
Sorry. I forgot the error when macro does not work (most of the time) is:
run-time error:'1004'
application-difined or object-difined error
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