Help! I am using this code to insert a picture into a ActiveX Image Box. The problem is that I double click on the box and nothing happens... I have a feeling that there might be a better code to run to get a open file box to appear when I click or double click on the box.
Any help would be much appriciated!
Thanks in advance!
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Private Sub Image1_DblClick(ByVal Cancel As MSForms.ReturnBoolean) Image1.Picture = LoadPicture(Application.GetOpenFilename) End Sub
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