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strokebow Value Error 09-27-2011, 01:50 PM
Whizbang Re: Inexplicable Value Error 09-27-2011, 01:57 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:13 PM
tlafferty Re: Inexplicable Value Error 09-27-2011, 02:08 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:11 PM
Whizbang Re: Inexplicable Value Error 09-27-2011, 02:18 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:32 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:34 PM
Marcol Re: Inexplicable Value Error 09-27-2011, 02:18 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:31 PM
Whizbang Re: Inexplicable Value Error 09-27-2011, 02:38 PM
Marcol Re: Inexplicable Value Error 09-27-2011, 02:38 PM
strokebow Re: Inexplicable Value Error 09-27-2011, 02:42 PM
Whizbang Re: Inexplicable Value Error 09-27-2011, 02:49 PM
Whizbang Re: Inexplicable Value Error 09-27-2011, 03:10 PM
strokebow Re: Inexplicable Value Error 09-28-2011, 05:00 AM
Whizbang Re: Inexplicable Value Error 09-28-2011, 08:37 AM
strokebow Re: Inexplicable Value Error 10-27-2011, 09:42 AM
snb Re: Inexplicable Value Error 10-27-2011, 09:48 AM
strokebow Re: Inexplicable Value Error 10-27-2011, 09:58 AM
  1. #1
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    Angry Value Error

    I get a #value error for my UDF which I have agonised over for hours/days. The code is:

    Function deltam(X As Variant, Y As Variant) As Double
    '..of a single peak.
        Dim YTenth As Double, XTenth1 As Double, XTenth2 As Double, I As Long, Temp As Double
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
            Exit Function
        End If
        YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
        I = 0
        Do
            I = I + 1                             'seeking the pair of points
            Temp = Y(I)
            If Y(I) >= YTenth Then                  'on the increasing branch
                XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
                Exit Do
            End If
        Loop
     
        Do
            I = I + 1                             'seeking the pair of points
            Temp = Y(I)
            If Y(I) <= YTenth Then                  'on the decreasing branch
                XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                Exit Do
            End If
        Loop
        deltam = XTenth2 - XTenth1
    End Function
    The X data is:

    98
    98.02
    98.04
    98.06
    98.08
    98.1
    98.12
    98.14
    98.16
    98.18
    98.2
    98.22
    98.24
    98.26
    98.28
    98.3
    98.32
    98.34
    98.36
    98.38
    98.4
    98.42
    98.44
    98.46
    98.48
    98.5
    98.52
    98.54
    98.56
    98.58
    98.6
    98.62
    98.64
    98.66
    98.68
    98.7
    98.72
    98.74
    98.76
    98.78
    98.8
    98.82
    98.84
    98.86
    98.88
    98.9
    98.92
    98.94
    98.96
    98.98
    99
    99.02
    99.04
    99.06
    99.08
    99.1
    99.12
    99.14
    99.16
    99.18
    99.2
    99.22
    99.24
    99.26
    99.28
    99.3
    99.32
    99.34
    99.36
    99.38
    99.4
    99.42
    99.44
    99.46
    99.48
    99.5
    99.52
    99.54
    99.56
    99.58
    99.6
    99.62
    99.64
    99.66
    99.68
    99.7
    99.72
    99.74
    99.76
    99.78
    99.8
    99.82
    99.84
    99.86
    99.88
    99.9
    99.92
    99.94
    99.96
    99.98
    100
    100.02
    100.04
    100.06
    100.08
    100.1
    100.12
    100.14
    100.16
    100.18
    100.2
    100.22
    100.24
    100.26
    100.28
    100.3

    ... and the Y data selected is:
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    0
    2
    4
    5
    11
    22
    30
    40
    49
    58
    74
    89
    89
    90
    72
    64
    38
    18
    3
    3
    0
    0
    1
    0
    0
    1

    If anyone can help me understand why I keep getting this error I will be very grateful!!!


    Thanks

  2. #2
    Forum Expert Whizbang's Avatar
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    Re: Inexplicable Value Error

    One thing I see is that you declare your function as a Double, and yet this line returns a string:
    deltam = "## Unequal Range Sizes##"
    I don't have a lot of experience with UDF's, but this seems potentially wrong.

    Additionally, between your two loops, you do not reset I, so this may lead to troubles.

    Also, this line:
    Temp = Y(I)
    Doesn't appear to do anything, since Temp is not used anywhere.


    I re-wrote your UDF to suit my own style:
    Function deltam(X As Variant, Y As Variant) As Variant
    '..of a single peak.
        Dim YTenth As Double, XTenth1 As Double, XTenth2 As Double, I As Long, Temp As Double
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
        Else
            YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
            I = 1
            Do Until Y(I) >= YTenth
                'seeking the pair of points
                I = I + 1       'on the increasing branch
            Loop
            
            XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
            
            I = 1
            
            Do Until Y(I) <= YTenth
                'seeking the pair of points
                I = I + 1           'on the decreasing branch
            Loop
            
            XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
            
            deltam = XTenth2 - XTenth1
            
        End If
    End Function
    Last edited by Whizbang; 09-27-2011 at 02:10 PM.

  3. #3
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    Re: Inexplicable Value Error

    Thank you tlafferty. Appreciate your help.

    I'll look in to that now. I wonder why it wouldn't complete the last part. Maybe because their is an issue with XTenth2?

  4. #4
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    Re: Inexplicable Value Error

    The issue seems to occur before the last step of code since it never seems to arrive. I've placed some stops in your code at critical junctures so you can watch it as it progresses. You will note that it never gets to the last stop:
    Function deltam(X As Variant, Y As Variant) As Double
    '..of a single peak.
        Dim YTenth As Double, XTenth1 As Double, XTenth2 As Double, I As Long, Temp As Double
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
            Exit Function
        End If
        YTenth = WorksheetFunction.Max(Y) / 10 'peak thenth of height
        I = 0
        Stop
        Do
            I = I + 1 'seeking the pair of points
            Temp = Y(I)
            If Y(I) >= YTenth Then 'on the increasing branch
                XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
                Exit Do
            End If
        Loop
    Stop
        Do
            I = I + 1 'seeking the pair of points
            Temp = Y(I)
    Stop
            If Y(I) <= YTenth Then 'on the decreasing branch
                XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                Exit Do
            End If
        Loop
    Stop
        deltam = XTenth2 - XTenth1
    Stop     'it never gets here
    End Function
    Hope this helps in your debug effort.
    If your question has been satisfactorily addressed, please consider marking it solved. Click the Thread Tools dropdown and select Mark thread as solved.
    Also, you might want to add to the user's reputation by clicking the star icon in the lower left corner of the post with the answer- it's why we do what we do...

    Thomas Lafferty
    Analyst/Programmer

  5. #5
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    Re: Inexplicable Value Error

    Thanks Whizbang for your suggestions.

    About 'I'...
    Ideally I should be set to be the correct index for when Y is a maximum.

    Because...

    The program looks at a generally bell shaped curve and find the points the X values that correspond to 10% of the y maximum.
    1. So initially Y max is found. Then we find 10% of Y max.
    2. Then we start to move along the x axis and examine the y value. When the Y value exceeds 10% of the max then we interpolate to find the corresponding X value where this occurs.
    3. Then (what my code was doing) was continuing on from the current index point and looking for the next y value that is less than 10% of y max. Then it interpolates to find the corresponding x value.
    It would be best if after 2 has finished we could move the index to the corresponding point where Y max is and continue to iterate from their to complete step 3.

    What do you think? Any ideas?

  6. #6
    Forum Expert Whizbang's Avatar
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    Re: Inexplicable Value Error

    First, it appears that posts were made while I was editing my code. So, please re-read my posted code to ensure you see my edited version.

    I am not quite following you. Please give my code a try (with and without the second I = 1), and let me know your response.

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    Re: Inexplicable Value Error

    Thanks Whizbag I understand your corrections however 'I' must not be reset back to 1

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    Re: Inexplicable Value Error

    I've run in the debug mode and I see the problem.

    As it iterates through in the second Do Loop, when I = I + 1 is > 108 it cuts out and goes out of context. I cant understand why??

    Since there are 115 entries in each column. Any ideas???

  9. #9
    Forum Guru (RIP) Marcol's Avatar
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    Re: Inexplicable Value Error

    You have multiple scenarios where a #DIV/0! error occurs and you have nothing in place to handle it

    e.g.
            If Y(I) <= YTenth Then                  'on the decreasing branch
                ' Handle #DIV/0! error when (Y(I) - Y(I + 1))=0
                XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                Exit Do
            End If
    Last edited by Marcol; 09-27-2011 at 02:23 PM.
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    Re: Inexplicable Value Error

    Thanks Marcol. That is another problem with the code although it is not causing the problem here.

    Thanks

  11. #11
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    Re: Inexplicable Value Error

    To account for the fact that there may never be an instance where Y(I) <= YTenth, you could do this:
    Function deltam(X As Variant, Y As Variant) As Variant
    '..of a single peak.
        Dim YTenth As Double
        Dim XTenth1 As Double
        Dim XTenth2 As Double
        Dim Temp As Double
        Dim I As Long
        
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
        Else
            YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
            I = 1
            Do Until Y(I) >= YTenth                         'on the increasing branch
                I = I + 1
            Loop
            
            XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
            
            Do Until Y(I) <= YTenth Or I > UBound(Y)        'on the decreasing branch
                I = I + 1
            Loop
            
            XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
            
            deltam = XTenth2 - XTenth1
            
        End If
    End Function

  12. #12
    Forum Guru (RIP) Marcol's Avatar
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    Re: Inexplicable Value Error

    All unhandled errors will cause your UDF to fail and return #VALUE!

    Seems others couldn't get past the lines I posted, so it would seem to be a good idea to at least start there.

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    Re: Inexplicable Value Error

    'I' is at 108. At 'I' = 117 one would expect the IF statement to become true and then XTenth2 to be set.

    But upon the next iteration after 108, everything goes out of context.

    Please see attached.
    Attached Images Attached Images

  14. #14
    Forum Expert Whizbang's Avatar
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    Re: Inexplicable Value Error

    Here is another version. It includes a check to make sure there will not be a Div/0 error, but it doesn't stop or otherwise handle the issue. It just skips past and moves on to the next Y()

    Function deltam(X As Variant, Y As Variant) As Variant
    '..of a single peak.
        Dim YTenth As Double
        Dim XTenth1 As Double
        Dim XTenth2 As Double
        Dim Temp As Double
        Dim I As Long
        
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
        Else
            YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
            For I = 1 To UBound(Y)
                If Y(I) >= YTenth And XTenth1 = 0 And (Y(I + 1) - Y(I)) <> 0 Then 
                    'on the increasing branch
                    XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
                End If
                If Y(I) <= YTenth And XTenth1 <> 0 And XTenth2 = 0 And (Y(I) - Y(I + 1)) <> 0 Then 
                    'on the decreasing branch
                    XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                End If
            Next I
            deltam = XTenth2 - XTenth1
            
        End If
    End Function
    Last edited by Whizbang; 09-27-2011 at 03:10 PM.

  15. #15
    Forum Expert Whizbang's Avatar
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    Re: Inexplicable Value Error

    Edited my last post to fix an error.

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    Re: Inexplicable Value Error

    Quote Originally Posted by Whizbang View Post
    Edited my last post to fix an error.
    Thanks Whizbang I really appreciate that. I like your style. However, I am reluctant to use one for loop for both operations in case there are any discrepancies in the peak and it has some fluctuations.

    I still can't understand why I = I + 1 would set itself back to 1 or go out of context. That doesn't make any sense to me?

  17. #17
    Forum Expert Whizbang's Avatar
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    Re: Inexplicable Value Error

    It is actually erroring out when I=109. As Marcol has said, there is no error handling in your original code. When I = 109, then "(Y(I) - Y(I + 1))" =0, which causes a Div/0 error and your function ceases and then returns the #Value error.

    Here is a simple error handler added to your original code:
    Function deltam(X As Variant, Y As Variant) As Variant
    '..of a single peak.
        Dim YTenth As Double, XTenth1 As Double, XTenth2 As Double, I As Long, Temp As Double
        
        On Error GoTo ErrHandler
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
            Exit Function
        End If
        YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
        I = 0
        Do
            I = I + 1                             'seeking the pair of points
            Temp = Y(I)
            If Y(I) >= YTenth Then                  'on the increasing branch
                XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
                Exit Do
            End If
        Loop
     
        Do
            I = I + 1                             'seeking the pair of points
            Temp = Y(I)
            If Y(I) <= YTenth Then                  'on the decreasing branch
                XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                Exit Do
            End If
        Loop
        deltam = XTenth2 - XTenth1
    Exit Function
    
    ErrHandler:
        MsgBox ("X.Count = " & X.Count & Chr(10) & _
                "Y.Count = " & Y.Count & Chr(10) & _
                "YTenth = " & YTenth & Chr(10) & _
                "XTenth1 = " & XTenth1 & Chr(10) & _
                "XTenth2 = " & XTenth2 & Chr(10) & _
                "I = " & I & Chr(10) & _
                "Y(I) = " & Y(I) & Chr(10) & _
                "Y(I + 1) = " & Y(I + 1))
        deltam = "#Error"
    
    End Function
    Last edited by Whizbang; 09-28-2011 at 11:25 AM.

  18. #18
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    Question Re: Inexplicable Value Error

    Hi peeps,

    Thanks so much for your suggestions.

    My apologies I left this for a while. So many things came up at work and home and I couldn't concentrate on this any longer but I have more time now :-)

    So I've implemented the code as follows:

    Function deltam(X As Variant, Y As Variant) As Variant
    '..of a single peak.
        Dim YTenth As Double, XTenth1 As Double, XTenth2 As Double, I As Long
        
        On Error GoTo ErrHandler
        
        If X.Count <> Y.Count Then
            deltam = "## Unequal Range Sizes##"
            Exit Function
        End If
        
        YTenth = WorksheetFunction.Max(Y) / 10    'peak thenth of height
        
        I = 0
        Do
            I = I + 1                             'seeking the pair of points
            If Y(I) >= YTenth Then                  'on the increasing branch
                XTenth1 = X(I) + ((YTenth - Y(I)) * (X(I + 1) - X(I))) / (Y(I + 1) - Y(I))
                Exit Do
            End If
        Loop
     
        Do
            I = I + 1                             'seeking the pair of points
            If Y(I) <= YTenth Then                  'on the decreasing branch
                XTenth2 = X(I) + ((YTenth - Y(I + 1)) * (X(I + 1) - X(I))) / (Y(I) - Y(I + 1))
                Exit Do
            End If
        Loop
        deltam = XTenth2 - XTenth1
    Exit Function
    
    ErrHandler:
       ' MsgBox ("X.Count = " & X.Count & Chr(10) & _
        '        "Y.Count = " & Y.Count & Chr(10) & _
         '       "YTenth = " & YTenth & Chr(10) & _
          '      "XTenth1 = " & XTenth1 & Chr(10) & _
           '     "XTenth2 = " & XTenth2 & Chr(10) & _
            '    "I = " & I & Chr(10) & _
             '   "Y(I) = " & Y(I) & Chr(10) & _
              '  "Y(I + 1) = " & Y(I + 1))
        deltam = "#Error"
    
    End Function
    Now I am getting an error for certain data. For example:
    =deltam(L386:L449,M386:M449)
    The data in question is:
    L M
    9.99 0
    9.9905 0
    9.991 0
    9.9915 0
    9.992 0
    9.9925 0
    9.993 0
    9.9935 0
    9.994 0
    9.9945 1
    9.995 1
    9.9955 2
    9.996 4
    9.9965 4
    9.997 4
    9.9975 6
    9.998 6
    9.9985 6
    9.999 7
    9.9995 7
    10 7
    10.0005 8
    10.001 8
    10.0015 8
    10.002 10
    10.0025 10
    10.003 10
    10.0035 11
    10.004 13
    10.0045 13
    10.005 14
    10.0055 15
    10.006 15
    10.0065 18
    10.007 19
    10.0075 19
    10.008 20
    10.0085 23
    10.009 24
    10.0095 25
    10.01 26
    10.0105 26
    10.011 31
    10.0115 32
    10.012 34
    10.0125 36
    10.013 36
    10.0135 37
    10.014 38
    10.0145 38
    10.015 39
    10.0155 39
    10.016 40
    10.0165 43
    10.017 43
    10.0175 41
    10.018 45
    10.0185 44
    10.019 44
    10.0195 40
    10.02 32
    10.0205 4
    10.021 0
    10.0215 0
    What should happen?
    This function finds deltam. Please see attached for illustration.

    Clearly, the function is complaining of an error somewhere. If anyone can please help me find out where this is, why this is and how I can overcome this to get my desired response I will be very grateful indeed?

    Thanks for your time. Please help and ask questions if I have not been clear.
    Attached Images Attached Images
    Last edited by strokebow; 10-27-2011 at 09:45 AM.

  19. #19
    Forum Expert snb's Avatar
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    Re: Inexplicable Value Error

    What strikes me as inexplicable is that you persist in not posting a sample workbook....



  20. #20
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    Re: Inexplicable Value Error

    Quote Originally Posted by snb View Post
    What strikes me as inexplicable is that you persist in not posting a sample workbook....
    My apologies snb.

    I've attached a sample workbook.

    As a side issues. I keep getting a circular reference message...
    Attached Files Attached Files

  21. #21
    Forum Expert snb's Avatar
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    Re: Inexplicable Value Error

    You can't assign an 'error message' to a 'double'.
    Dividing by zero is a problem.
    In your function you want to divide by the next value in column B minus the curernt value. Most of the time that result is 1; dividing by 1 seems to me to be rather redundant.
    I'd change the function into:

    Function deltam(X As Range, Y As Range)
     If X.Count <> Y.Count Then Exit Function
        
     sx = X
     sy = Y
     YTenth = WorksheetFunction.Max(Y) / 10
    
     For j = 1 To UBound(sy)
      If IsEmpty(XTenth1) Then
       If sy(j, 1) >= YTenth Then XTenth1 = sx(j, 1) + ((YTenth - sy(j, 1)) * (sx(j + 1, 1) - sx(j, 1)))
      ElseIf sy(j, 1) <= YTenth Then
       XTenth2 = sx(j, 1) + ((YTenth - sy(j, 1)) * (sx(j + 1, 1) - sx(j, 1)))
       Exit For
      End If
     Next
    
     If j <= UBound(sy) Then deltam = XTenth2 - XTenth1
    End Function
    Last edited by snb; 10-27-2011 at 11:06 AM.

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