How to open .jpg picture with macro

Good Morning SHG

Your code works, but I would like to better understand the code.

Could you explain to me how this line of code works or the meanings of code please:

RetVal = ShellExecute(0&, "open", PicPath, 0&, 0&, 1)

Hello Matt,

I will keep it simple because this is a low level system call. Explaining how all the arguments function and where they come from is too much detail to explain in this post.

The ShellExecute code is an API (Applications Programming Interface) call. The procedure will open the executable program associated with the file's extension. This call uses uses the verb "open" to run the executable program for the file's type. The file, including the path and the file extension, is the third parameter. The last parameter determines the window state when the program is run. Normal size is chosen.

Good Morning SHG

Your code works ...

Leith's code, Matt

Good Morning Leith

RetVal = ShellExecute(0&, "open", PicPath, 0&, 0&, 1)

I understand RetVal = ShellExecute( ?, "open, PicPath, ?, ?, ?)

Is their an easy explaination of the areas with question marks ? In general, what they mean.

If not, forget it, as I understand where you are coming from.

Hello Matt,

Click on this link to see a full explanation of the call.