There are 4 different values A,B,C,D and seven columns (1-7). How to fill all possible combinations i.e. 7^4 I guess. e.g AAAAAAA,AAAAAAB ...
So there will be 2401 rows with all possible combinations
Thanks
There are 4 different values A,B,C,D and seven columns (1-7). How to fill all possible combinations i.e. 7^4 I guess. e.g AAAAAAA,AAAAAAB ...
So there will be 2401 rows with all possible combinations
Thanks
Last edited by subrato312; 05-03-2017 at 08:09 AM.
So AAAAAAB is the same as BAAAAAA ?
because if not then you are not simply looking for combinations, and it will result in 16384 values.
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There are 10 kinds of people in this world... those who understand binary, and those who don't.
If the position of the B in the above does matter, meaning AAAAAAB and AAAAABA are different, then this code ought to work:
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Here's a non-VBA spreadsheet formula based solution that seems like it should work: https://www.excelforum.com/tips-and-...ml#post4640511
Originally Posted by shg
Thank you so much
Yeah its 4^7=16384 Thanks!!!
Happy to help![]()
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