Speed Networking Seating Schedule

Is this really solvable ?

8 people are around a table, the second round they don't want to hear each other again, so each needs to go to a different table, but there are only 6 tables?

round 1
person 1 Table one
person 2 Table one
person 3 Table one
person 4 Table one
person 5 Table one
person 6 Table one
person 7 Table one
person 8 Table one


round 2
person 1 Table one with 7 others
person 2 table two with 7 others
person 3 table three with 7 others
person 4 table four with 7 others
person 5 table five with 7 others
person 6 table six with 7 others
person 7 ?
person 8 ?


How can they not hear someone again where do persons 7 and 8 go, or am I misunderstanding something? The key is that attendees only see each other 1 time at most.

to solve, tables needs to be considerably more than people at a table, otherwise if it is only once you hear a commercial you will never get a solution. tables =people-1 easy, you just rotate everyone every minute

and it is a very old post if i read the dates!