I'm a bit uncertain if my named range has turned out the way i want it to.. Is their anyway of finding the dimensions of my namned range, i.e. # of rows and columns?
I'm a bit uncertain if my named range has turned out the way i want it to.. Is their anyway of finding the dimensions of my namned range, i.e. # of rows and columns?
Select the range in the name box and have a look.. Unless it's a dynamic range in which case use the function manager
Elegant Simplicity............. Not Always
1. Select the Function Manager
2. Select your dynamic range from the list
3. Put you cursor into the formula display at the bottom.
............ Excel will highlight the range as it does when you copy
I still don't know if understand what you mean (because i dont know what you mean by the "function manager", google couldn't tell me either. Guess you mean the "formula builder"?), do you mean that i should:
in any cell in the same sheet as the named range is, type
and then that should highlight my range![]()
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Because I don't think that works when my named range is a VLOOKUP function, it highlights the array from which the vlookup is based (I think)
Last edited by vizzkid; 04-12-2013 at 11:13 AM.
a vlookup function returns one result so not much to test as dimensions go ;-)
Josie
if at first you don't succeed try doing it the way your wife told you to
Sorry no not the Function Manager - The "Name" manager............ (unsurprisingly)
Not if you specify the function to return several columns..
eg
will return a matrix/row vector of dimension 1x3![]()
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Didn't really find an answer to my original question, couldn't get your technique to work AndyLitch. I might be stupid or it's a mac thing. However, it's no longer an issue as my named range sorted itself out.
Thanks for replies!
Last edited by vizzkid; 04-16-2013 at 08:34 AM.
true-that's not really typical though (an INDEX/MATCH would be usual) so you might have mentioned it ;-)
anyway at least you have it working
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