Given the <= operator the CEILING formula you've been given does exactly what you ask.
The formula takes the value in F2 and rounds up to next nearest multiple of 5000 - and then multiplies that final value by 0.01%
Please test before disregarding based on interpretation.
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Sorry! I tested, but while writing the message here wrote something else.
It was my mistake that i was not able to state the problem correctly in the last post. Pardon me.
I was about to ask, what modification to the formula shall be made so that it takes into account the < condition and not <=.
see post # 2
Hi
I am looking for a formula which calculates value according to the following condition.
Here is a rough formula of what i am looking for:-
The same thing goes on with multiples of 5000. [IF greater than 10000 but less than 15000, then 15000*0.01%, IF greater than 15000 but less than 20000, then 20000*0.01% .........]![]()
=IF(F2<5000, (5000*0.01%), "", IF(F2>5000 BUT <10000, (10000*.01%), "" ))
-Thanks
yet again, see post # 2
Thanks for both of the formula and sorry for asking the same question again and again![]()
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