If you're already entering the number .8 into a cell, to get the correct value just use
=150*B1
Where B1 contains .8
Or are you trying to calculate the .8 based on the number of minutes you input?
If you're already entering the number .8 into a cell, to get the correct value just use
=150*B1
Where B1 contains .8
Or are you trying to calculate the .8 based on the number of minutes you input?
Yes I am trying to calculate the number basedon the numbers of minutes I input and the amount
Last edited by DonkeyOte; 12-09-2009 at 03:59 AM. Reason: removed unnec. quote
If you gave some examples of your "entries" that would help as I think that's what's preventing you from getting a quick resolution.
If you're saying you work 3 hours and 36 minutes and you enter that into say A1 as
3:36
then to get your total you could use something like
would generate 555![]()
=150*SUM(HOUR(A1),(MATCH(MINUTE(A1),{0,1,6,13,19,25,31,36,41,47,53})-1)/10)
change the values in in the line array to match your requirements - you must leave the 0 though... in the above 1-5 would generate 0.1, 6-12 -> 0.2 etc...
It's a shame you need to specify like the above as obviously
=150*(CEILING(A1*24,0.1))
is a lot simpler but in this case would generate 540
My Recommended Reading:
Volatility
Sumproduct & Arrays
Pivot Intro
Email from XL - VBA & Outlook VBA
Function Dictionary & Function Translations
Dynamic Named Ranges
I am attaching an example of the entries that I am doing. I am not entering any formulas yet.
I hope it helps
Last edited by Paul; 12-09-2009 at 10:50 PM. Reason: removed full post quotation
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