I want to use VBA to delete a row if it contains exactly the same data as another. I have been using this:

Public Sub DeleteDuplicateRows()
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' DeleteDuplicateRows
' This will delete duplicate records, based on the Active Column. That is,
' if the same value is found more than once in the Active Column, all but
' the first (lowest row number) will be deleted.
'
' To run the macro, select the entire column you wish to scan for
' duplicates, and run this procedure.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''

Dim R As Long
Dim N As Long
Dim V As Variant
Dim Rng As Range


Application.ScreenUpdating = False
Application.Calculation = xlCalculationManual


Set Rng = Application.Intersect(ActiveSheet.UsedRange, _
                    ActiveSheet.Columns(ActiveCell.Column))

Application.StatusBar = "Processing Row: " & Format(Rng.Row, "#,##0")

N = 0
For R = Rng.Rows.Count To 2 Step -1
If R Mod 500 = 0 Then
    Application.StatusBar = "Processing Row: " & Format(R, "#,##0")
End If

V = Rng.Cells(R, 1).Value
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Note that COUNTIF works oddly with a Variant that is equal to vbNullString.
' Rather than pass in the variant, you need to pass in vbNullString explicitly.
'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
If V = vbNullString Then
    If Application.WorksheetFunction.CountIf(Rng.Columns(1), vbNullString) > 1 Then
        Rng.Rows(R).EntireRow.delete
        N = N + 1
    End If
Else
    If Application.WorksheetFunction.CountIf(Rng.Columns(1), V) > 1 Then
        Rng.Rows(R).EntireRow.delete
        N = N + 1
    End If
End If
Next R


End Sub

but it will only delete rows based on data from 1 column. I know this is a simple one - I just can't find the answer. Cheers.