=1000*(1 + 10%)^N where N is the number of years
=1000*(1 + 10%)^N where N is the number of years
Entia non sunt multiplicanda sine necessitate
This formula gives me the amount for each year, but I need a cumulative total of all the amounts for a given year. In my example, I need to formula that returns 2310 for year 2, and 3641 for year three. Thanks in advance for your help.
=amt * ((1 + int) ^ (N + 1) - 1) / int
... where amt is the initial amount, N is the number of periods, and int is the compounding rate, e.g.,
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-A- ----B---- -------------------------C------------------------- 1 amt 1,100.00 2 int 10% 3 4 N Sum 5 0 1,100.00 B5 and down: =amt * ((1 + int) ^ (N + 1) - 1) / int 6 1 2,310.00 7 2 3,641.00 8 3 5,105.10 9 4 6,715.61
This formula works great with one exception. If I try to calculate without using a compounding rate, which will need to be done in some cases, it results in a division by 0 error and does not let me calculate the cumulative totals by year with zero interest.
=if(int=0, (N+1) * amt, ~)
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