OOps, I've copied the formula down and now I get a void where there
shouldn't be voids but should be values. Any thoughts?
"shaunap" wrote:
> Thank you very much! Worked great.
>
> "Bob Phillips" wrote:
>
> > I think that you want
> >
> > =IF(ISNUMBER(MATCH("VOID",'Cheque Register'!E$2:E$195)),"VOID",
> > SUMIF('Cheque Register'!A$2:A$195,B47,'Cheque Register'!C$2:C$195))
> >
> > --
> >
> > HTH
> >
> > Bob Phillips
> >
> > (replace xxxx in the email address with gmail if mailing direct)
> >
> > "shaunap" <shaunap@discussions.microsoft.com> wrote in message
> > news:7F142A94-88C2-4F4D-9C4C-BE08ED7A967A@microsoft.com...
> > > Hi there,
> > >
> > > I'm having an issue with a formula of mine. My data is 5 columns wide. I
> > > have the formula listed below to retrieve the value of column C if column
> > A
> > > matches a set value. Unless column E states "VOID". Then I want the value
> > > input to be "Void". The formula kinda works. It gets the value of column
> > C
> > > if column E is not void, but if column E states void then I get a 0.
> > Column
> > > E is a formula in itself looking at column D for a value of 1. I tried
> > > changing the formula below to search column D instead of E for a 1 instead
> > of
> > > a void and then it returns the value of column C regardless of what it
> > finds.
> > >
> > > {=SUM(IF('Cheque Register'!A$2:A$195=B47,IF('Cheque
> > > Register'!E$2:E$195="VOID","VOID",'Cheque Register'!C$2:C$195),0))}
> > >
> > > I'm not sure what I'm missing, the logic seems clear to me, but obviously
> > > the computer thinks otherwise. If anybody out there can help me I'd
> > > appreciate it.
> > >
> > > Thanks,
> > > Shauna
> >
> >
> >
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