Thank you very much! Worked great.
"Bob Phillips" wrote:
> I think that you want
>
> =IF(ISNUMBER(MATCH("VOID",'Cheque Register'!E$2:E$195)),"VOID",
> SUMIF('Cheque Register'!A$2:A$195,B47,'Cheque Register'!C$2:C$195))
>
> --
>
> HTH
>
> Bob Phillips
>
> (replace xxxx in the email address with gmail if mailing direct)
>
> "shaunap" <shaunap@discussions.microsoft.com> wrote in message
> news:7F142A94-88C2-4F4D-9C4C-BE08ED7A967A@microsoft.com...
> > Hi there,
> >
> > I'm having an issue with a formula of mine. My data is 5 columns wide. I
> > have the formula listed below to retrieve the value of column C if column
> A
> > matches a set value. Unless column E states "VOID". Then I want the value
> > input to be "Void". The formula kinda works. It gets the value of column
> C
> > if column E is not void, but if column E states void then I get a 0.
> Column
> > E is a formula in itself looking at column D for a value of 1. I tried
> > changing the formula below to search column D instead of E for a 1 instead
> of
> > a void and then it returns the value of column C regardless of what it
> finds.
> >
> > {=SUM(IF('Cheque Register'!A$2:A$195=B47,IF('Cheque
> > Register'!E$2:E$195="VOID","VOID",'Cheque Register'!C$2:C$195),0))}
> >
> > I'm not sure what I'm missing, the logic seems clear to me, but obviously
> > the computer thinks otherwise. If anybody out there can help me I'd
> > appreciate it.
> >
> > Thanks,
> > Shauna
>
>
>
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