I'm not sure this is what you're looking for, but try the following...
Insert > Name > Define
Name: BigNum
Refers to:
=9.99999999999999E+307
Click Ok
Then, try...
=LOOKUP(BigNum,CHOOSE({1,2},COLUMNS(A1:E5),MATCH(0,MMULT({1,1,1,1,1},--(A
1:E5="A")),0)-1))
In article <FCFF5521-C0EC-42C5-B883-1CEEB055D778@microsoft.com>,
SteveC <SteveC@discussions.microsoft.com> wrote:
> Thanks for trying to figure this out.
>
> Forget everything I just said. Let's start begin this way:
>
> Example 1:
> Count the number of times A is in the series A1:E5. You should Count 5.
>
> Col A Col B Col C Col D Col E
> Row1 A A
> Row2 A
> Row3 A
> Row4 A
> Row5
>
> Example 2:
> Now Count the number of consecutive times A appears in the series, starting
> from ColA and finishing at ColE. The key word is "consecutive." You should
> could count 2. This is because there is no "A" in Col C. The formula should
> stop counting everything after the break in the series.
>
> Col A Col B Col C Col D Col E
> Row1 A
> Row2 A
> Row3 A
> Row4 A
> Row5
>
> My question is, what formula in G1 will count the consecutive number of "As"
> in the series A1:E5. That is, what formula will return a value of 2.
>
> Thanks for taking a look...
>
> (this is easily solvable via a sorting macro or multiple vlookups in A1:E5,
> but I wanted to see if it's possible in the way described above...)
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