Counting unique text/number cells from a range

Please consider a long range of text cells containing A, B, C, D....Z and more.

Lets say it goes from H1 to H1500

A ->H1
A
B
F
D
A
H
D
.
.
.
.
K->H1500

I understand that to count the number of A's, we have:
=countif(=H1:H1500,"A")

Similarly, =countif(H1:H1500,"B") for B
.
.
.
.

But to this for every text is tedious.....

Is there a unique WAY which will actually give the count of each different text/number cells , once a range is selected.


Thanks for your time,
Sudeep

Try...

=SUMPRODUCT((H1:H1500<>"")/COUNTIF(H1:H1500,H1:H1500&""))

Hope this helps!

In article <sudeepd12.1qmzqc_1118786798.0235@excelforum-nospam.com>,
sudeepd12 <sudeepd12.1qmzqc_1118786798.0235@excelforum-nospam.com>
wrote:

> Please consider a long range of text cells containing A, B, C, D....Z
> and more.
>
> Lets say it goes from H1 to H1500
>
> A ->H1
> A
> B
> F
> D
> A
> H
> D

Thanks for the command. It gives the number of distinctive or unique values in the range.

Could you suggest a way to get the count of each of the repetitive values without having to specify each using the COUNTIF command.

For instance
-----------
jbushnel -->A1
jbreen
jthayer
rrobinson
ajagmag
jthayer
jbushnel -->A7
-----------

I am looking for a formula which will split the results as:

A8--> jbushnell 2-->B8
jthayer 2
rrobinson 1
ajagmag 1
jbreen 1

Is this possible?Please let me know. Thanks for your time.

Regards,
Sudeep

Try...

B8, copied down:

=COUNTIF($A$1:$A$7,A8)

Hope this helps!

Originally Posted by sudeepd12

Thanks for the command. It gives the number of distinctive or unique values in the range.

Could you suggest a way to get the count of each of the repetitive values without having to specify each using the COUNTIF command.

For instance
-----------
jbushnel -->A1
jbreen
jthayer
rrobinson
ajagmag
jthayer
jbushnel -->A7
-----------

I am looking for a formula which will split the results as:

A8--> jbushnell 2-->B8
jthayer 2
rrobinson 1
ajagmag 1
jbreen 1

Is this possible?Please let me know. Thanks for your time.

Regards,
Sudeep