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Average Row Formula

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  1. #1
    Tom
    Guest

    Average Row Formula

    Is there a way to calculate the average of a row if some cells are
    empty but when calculating the average they should have the value of
    the cell to the left?

    If the following data is enterered

    A B C D E F G

    1 3 5 6

    For the calculation the cells should use the data

    A B C D E F G

    1 3 3 3 5 5 6

    Also what would the average formula be if you wanted to skip one of the
    cells from the average calculation?

    Thanks

    Tom


  2. #2
    Don Guillett
    Guest

    Re: Average Row Formula

    pls do NOT multipost. It wastes resources

    --
    Don Guillett
    SalesAid Software
    donaldb@281.com
    "Tom" <tsanders123@hotmail.com> wrote in message
    news:1115469850.440080.158390@g14g2000cwa.googlegroups.com...
    > Is there a way to calculate the average of a row if some cells are
    > empty but when calculating the average they should have the value of
    > the cell to the left?
    >
    > If the following data is enterered
    >
    > A B C D E F G
    >
    > 1 3 5 6
    >
    > For the calculation the cells should use the data
    >
    > A B C D E F G
    >
    > 1 3 3 3 5 5 6
    >
    > Also what would the average formula be if you wanted to skip one of the
    > cells from the average calculation?
    >
    > Thanks
    >
    > Tom
    >




  3. #3
    Jerry W. Lewis
    Guest

    Re: Average Row Formula

    Answered in microsoft.public.excel

    Jerry

    Tom wrote:

    > Is there a way to calculate the average of a row if some cells are
    > empty but when calculating the average they should have the value of
    > the cell to the left?
    >
    > If the following data is enterered
    >
    > A B C D E F G
    >
    > 1 3 5 6
    >
    > For the calculation the cells should use the data
    >
    > A B C D E F G
    >
    > 1 3 3 3 5 5 6
    >
    > Also what would the average formula be if you wanted to skip one of the
    > cells from the average calculation?
    >
    > Thanks
    >
    > Tom



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