Hi Jim,

Another version for you :-)

Function ColumnLetter(rng As Range) As String
ColumnLetter = Split(Columns(rng.Column).Address(, False), ":")(1)
End Function


--

HTH

RP
(remove nothere from the email address if mailing direct)


"Jim May" <jmay@cox.net> wrote in message
news:v5pae.26134$gV.17101@lakeread02...
> Hank - Thanks,,,
> CRAP!! -- I had them both in my Sheet1 module
> versus a Standard Module..
> Thanks,
> Jim
>
>
> "Hank Scorpio" <ApolloXVIII@Hates.Spam> wrote in message
> news:lq6k619uh1pqqqbjsct4d1jbsui8nj3g7s@4ax.com...
> > On Sat, 23 Apr 2005 05:46:45 -0400, "Jim May" <jmay@cox.net> wrote:
> >
> > >Both these functions are yielding/displaying the #NAME?
> > >in cell A1 which contains either =ColumnLetter(AB5) or
> ColumnLetter($AB$5)
> > >or
> > >ColLetter(AB5) or ColLetter($AB$5)..
> > >Any ideas as to why?
> > >Thanks in Advance
> >
> > Best guess; you have the function definitions in a different workbook
> > from the workbook that you have the formulas in.
> >
> > If the functions below are in your Personal.xls workbook (say), then
> > this:
> > =PERSONAL.XLS!ColumnLetter(AC15)
> >
> > should work, but this:
> > =ColumnLetter(AB5)
> >
> > gives me the result you describe.
> >
> > You might also consider saving the functions into an add-in. (.xla)
> >
> > >Function ColumnLetter(Rng As Range) As String
> > >ColumnLetter = Left(Rng.Range("A1").Address(True, False), _
> > > InStr(1, Rng.Range("A1").Address(True, False), "$", 1) - 1)
> > >End Function
> > >
> > >
> > >Function ColLetter(Rng As Range) As String
> > > ColLetter = Left(Rng.Address(False, False), _
> > > 1 - (Rng.Column > 26))
> > >End Function
> >
> >
> > ---------------------------------------------------------
> > Hank Scorpio
> > scorpionet who hates spam is at iprimus.com.au (You know what to do.)
> > * Please keep all replies in this Newsgroup. Thanks! *
>
>