I have two columns in an Excel spreadsheet that consist of an address in each
column. Most of the addresses are identical but I wish to find the rows
where the addresses are not identical.
Is there a way to do this.
Thanks for any help.
Kris
I have two columns in an Excel spreadsheet that consist of an address in each
column. Most of the addresses are identical but I wish to find the rows
where the addresses are not identical.
Is there a way to do this.
Thanks for any help.
Kris
Hi,
Assuming that you know that the addresses to be compared are on the same row(s), you could try a simple IF statement in an adjacent column like this:
=IF(A3=C3,"ok","ERROR")
If you have a lot of addresses, you could then filter on the new column and select the ERROR cells.
-- George
Hi,
One way would be to conditional format one column so it highlights if it
doesn't equal the corresponding cells in the other column.
HTH
Ron
"kharrison" wrote:
> I have two columns in an Excel spreadsheet that consist of an address in each
> column. Most of the addresses are identical but I wish to find the rows
> where the addresses are not identical.
>
> Is there a way to do this.
>
> Thanks for any help.
> Kris
Can you explain how I would go about doing that.
Thanks
"Airfive" wrote:
> Hi,
>
> One way would be to conditional format one column so it highlights if it
> doesn't equal the corresponding cells in the other column.
>
> HTH
> Ron
>
> "kharrison" wrote:
>
> > I have two columns in an Excel spreadsheet that consist of an address in each
> > column. Most of the addresses are identical but I wish to find the rows
> > where the addresses are not identical.
> >
> > Is there a way to do this.
> >
> > Thanks for any help.
> > Kris
If you want help working with duplicates, take a trip to Chip Pearson's
site:
http://www.cpearson.com/excel/duplicat.htm
He has a bunch of techniques for working with duplicates.
kharrison wrote:
>
> I have two columns in an Excel spreadsheet that consist of an address in each
> column. Most of the addresses are identical but I wish to find the rows
> where the addresses are not identical.
>
> Is there a way to do this.
>
> Thanks for any help.
> Kris
--
Dave Peterson
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