You cannot pass 1 dimension of the array to the sub AFAIK, but you can pass
1 element

Type myType
x As Long
y As Long
End Type

Sub mySub(theArray As myType)
With theArray
.x = .x * 2
.y = .y * 2
End With
End Sub


Sub Main()
Dim myArray(20, 20) As myType, x
For x = 0 To 20
myArray(x, 1).x = 100 + x
myArray(x, 1).y = 200 + x
MsgBox "x=" & myArray(x, 1).x & ", Y=" & myArray(x, 1).y
mySub myArray(x, 1)
MsgBox "x=" & myArray(x, 1).x & ", Y=" & myArray(x, 1).y
Next x
End Sub



--
HTH

Bob Phillips

"Cactus [ÏÉÈËÇò]" <a@b.com> wrote in message
news:OBsyDaCAFHA.3924@TK2MSFTNGP15.phx.gbl...
> Hi Tom
>
> I want the argument is a part of array.
> but VBA said that is wrong language grammar.
>
>
> Sub mySub(theArray() As myType)
> For y = 0 to 20
> theArray(y).X = 1
> theArray(y).Y = 2
> Next y
> End Sub
>
>
> Sub Main()
> Dim myArray(20, 20) As myType
> For x = 0 to 20
> mySub myArray(x)
> 'I think myArray(x) should a array "myArray(20) As myType"
> Next x
> End Sub
>
>
> "Tom Ogilvy" <twogilvy@msn.com> дÈëÓʼþ
> news:ezk2wP9$EHA.2076@TK2MSFTNGP15.phx.gbl...
> > Type myType
> > X As Long
> > Y As Long
> > End Type
> >
> >
> > Sub MySub1()
> > Dim myArray(20, 20) As myType
> > For i = LBound(myArray, 1) To UBound(myArray, 1)
> > For j = LBound(myArray, 2) To UBound(myArray, 2)
> > myArray(i, j).X = Int(Rnd() * 10000 + 1)
> > myArray(i, j).Y = Int(Rnd() * 10000 + 1)
> > Next
> > Next
> > mySub myArray
> > End Sub
> >
> >
> > Sub mySub(theArray() As myType)
> > i = Int(Rnd() * 20 + 1)
> > j = Int(Rnd() * 20 + 1)
> > MsgBox "MyArray(" & i & "," & _
> > j & ").X=" & theArray(i, j).X & _
> > vbNewLine & _
> > "MyArray(" & i & "," & _
> > j & ").Y=" & theArray(i, j).Y
> > End Sub
> >
> > as an example.
> >
> > --
> > Regards,
> > Tom Ogilvy
> >
> > "Cactus [ÏÉÈËÇò]" <a@b.com> wrote in message
> > news:OY%23iFb7$EHA.3472@TK2MSFTNGP14.phx.gbl...
> > > Thank Bob
> > >
> > > I read VBA help, to define a 2D array use
> > >
> > > Dim myArray(20,20) as myType
> > >
> > > Now I get next block.
> > >
> > > How send the 2D Array as Argument?
> > >
> > > Sub mySub(theArray() As myType)
> > >
> > > End Sub
> > >
> > >
> > >
> > >
> > >
> > > "Bob Phillips" <phillips@tiscali.co.uk> дÈëÓʼþ
> > > news:Oqv7tE7$EHA.3708@TK2MSFTNGP14.phx.gbl...
> > > > I think this is what you mean
> > > >
> > > > Dim myarray() As myType
> > > >
> > > > ReDim myarray(1 To 20)
> > > > myarray(1).X = 1
> > > > myarray(1).Y = 3
> > > >
> > > > Const cLen As Long = 20
> > > > Dim myArray2(cLen) As myType
> > > >
> > > > myArray2(20).X = 1
> > > > myarray(20).Y = 2
> > > >
> > > >
> > > > --
> > > > HTH
> > > >
> > > > Bob Phillips
> > > >
> > > > "Cactus [ÏÉÈËÇò]" <a@b.com> wrote in message
> > > > news:%23jEO4n4$EHA.3908@TK2MSFTNGP12.phx.gbl...
> > > > > I want to use a typed data of array.
> > > > >
> > > > > Type myType
> > > > > X As Long
> > > > > Y As Long
> > > > > End Type
> > > > >
> > > > > Dim myMatrix(20)(20) As myType
> > > > >
> > > > > But above code is wrong.
> > > > > How to that right VBA coding?
> > > > >
> > > > > Another question.
> > > > > Can I use a Variant array such as
> > > > >
> > > > > dim myVar as Long = 20
> > > > > Dim myMatrix(myVar) As myType
> > > > >
> > > > >
> > > > > Thanks...
> > > >
> > > >
> > >
> >
> >
>