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Hello..
I have an issue on the countifs formula where it requires repetitions. Is there any way I can simplify or any approach I will make to get the result. Attaching the sheet I had prepared and the question is at the bottom.
Hello..
I have an issue on the countifs formula where it requires repetitions. Is there any way I can simplify or any approach I will make to get the result. Attaching the sheet I had prepared and the question is at the bottom.
Hi,
Formula:
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Too late now of course but had you designed the table in a normalised/regularised data table you'd have been able to use a Pivot Table to analyse and get all sorts of data results without the need for any formulae
Last edited by Richard Buttrey; 06-10-2020 at 05:13 AM.
Richard Buttrey
RIP - d. 06/10/2022
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The even rows contain 'work, so your formula will never give an above 0 result. However, this might be what you think you want:
=COUNTIFS($K$4:$K$346,"Q",$K$5:$K$347,"J")
Notice the two arrays are offset from each other by one row.
Ali
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Hi Ali,
Thank you it worked very well. So what that means if the even row contains "work"?
H Richard,
Been thinking using the pivot but this was the format the top management want to see but thanks to your formula. Made my life easier. Great stuff.
Only you can tell us that. It's your data.
If that takes care of your original question, please select Thread Tools from the menu link above and mark this thread as SOLVED.
What I meant is this?
(Notice the two arrays are offset from each other by one row.)?
Why do we have to offset it? Thanks.
Because you want to count "J" in the odd rows where the even rows immediately above them contain "Q".
$K$5:$K$347,"J" - odd rows (5, 7, 9, etc.)
$K$4:$K$346,"Q" - even rows (4, 6, 8, etc.)
Excel 2016 (Windows) 32 bit
Sheet: Records (2)
Last edited by AliGW; 06-11-2020 at 01:41 AM.
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