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If every 5 days late . . .

  1. #1
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    If every 5 days late . . .

    Hey guys,

    I cannot find help with this anywhere so please pardon me if it has been mentioned previously.

    I am trying to create a formula that will allow me do see what my penalty would be for being late with submitting my deliverable.

    See Attached Book30.xlsx

    Here is the following criteria that I need to be met:

    If the Site ID has a completion date, but does not have a deliverable complete day within 5 days of the complete date, a penalty of $5 must be tallied up for every 5 days the deliverable is delinquent.

    So for Site PID01, the Penalty would continue to calculate until there was a Deliverable Complete Date.

    For PID011, there would be a penalty value that is relative to how many times they were 5 days late between 10/2/2014 and 2/10/2015.

    Let me know if you need clarification.
    Attached Files Attached Files

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    Re: If every 5 days late . . .

    Hello All,

    I have tried to no avail to get this to work.

    See Attached Book30.xlsx

    The only way I knew to do it was to add 2 columns. Column D is supposed to tally how many days late. column E is supposed to divide column D by 5. And column F will multiply column E by $5.

    I can't get my formula to work in column D2 in order to calculate total days late. I am trying to get it to tell me how many days late the deliverable is if there is not a date entered in column C. FYI - our system generates 1/1/1900 as a value so I have to use this as a baseline.

    I am getting a negative value in Column D5.

    Any help is greatly appreciated!

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    Re: If every 5 days late . . .

    :'( can anyone let me know what I am doing wrong?

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    Re: If every 5 days late . . .

    Maybe ...

    Row\Col
    B
    C
    D
    E
    1
    Due
    Delivered
    Late (5-day increments)
    2
    01/02/2015
    01/07/2015
    1
    D2: =MAX(0, INT((C2-B2)/5))
    3
    08/24/2014
    09/11/2014
    3
    4
    07/13/2014
    07/29/2014
    3
    5
    09/02/2014
    09/14/2014
    2
    6
    10/02/2014
    09/30/2014
    0
    Entia non sunt multiplicanda sine necessitate

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    Re: If every 5 days late . . .

    But what if C:C has a value of 1/1/1900?

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    Re: If every 5 days late . . .

    Our Database will return the value of 1/1/1900 if the delivered date is not yet actual. I still need a way to do a formula that if = 0 or 1/1/1900 change the value to "Today" and then do the subtraction from the Due date to find out the 5 day increments.

  7. #7
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    Re: If every 5 days late . . .

    Row\Col
    B
    C
    D
    E
    1
    Due
    Delivered
    Late (5-day increments)
    2
    01/15/2015
    01/19/2015
    0
    D2: =MAX(0, INT((IF(C2=1, TODAY(), C2) - B2) / 5))
    3
    01/15/2015
    01/20/2015
    1
    4
    01/15/2015
    01/21/2015
    1
    5
    01/15/2015
    01/25/2015
    2
    6
    01/15/2015
    01/01/1900
    5
    7
    01/20/2015
    01/01/1900
    4
    8
    01/25/2015
    01/01/1900
    3

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