Well, I changed that, but found it behaved pretty much like the solution SDCh offered, namely that:
if f3=16 and f7=23, then f8=Free. However. one of the conditions needed is that to indicate "free", f3 eeded to be 15 or less AND f5 had to be 22 or less.
Neither of those 2 conditions was met in this example, yet "Free" is still the result.
Again NU2vba, thank you for trying.
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