I have explanation for you.
First of all we will observe two columns A and B. In column A we have numbers from 1 to 10 with step of 1 and on B from 10 to 100 with step of 10.
If you write A1:A10^{2;1;0;0} and with a standard method (choose a property range (4 col. and 10 rows) and ctr+shift+enter) execute this. You will get the matrix of 4 columns and 10 rows.
You will get something like this:
A^2 A A^0 A^0
1 1 1 1
4 2 1 1
9 3 1 1
16 4 1 1
25 5 1 1
36 6 1 1
49 7 1 1
64 8 1 1
81 9 1 1
100 10 1 1
And now you write B1:B10^{0;0;1;2} and with a standard method (choose a property range (4 col. and 10 rows) and ctr+shift+enter) execute this. You will get the matrix of 4 columns and 10 rows.
You will get something like this:
B^0 B^0 B^1 B^2
1 1 10 100
1 1 20 400
1 1 30 900
1 1 40 1600
1 1 50 2500
1 1 60 3600
1 1 70 4900
1 1 80 6400
1 1 90 8100
1 1 100 10000
And on last we have A1:A10^{2;1;0;0}*B1:B10^{0;0;1;2}.
And we will get this:
A^2 A B B^2
1 1 10 100
4 2 20 400
9 3 30 900
16 4 40 1600
25 5 50 2500
36 6 60 3600
49 7 70 4900
64 8 80 6400
81 9 90 8100
100 10 100 10000
Better explanation in the picture below.
aha111.jpg
Now the right question is WHY in this format and WHY is only 4 colums?
The trick is in part of {0;0} on the bouth side.
The first column of the first matrix is multiplied with the first column of the second matrix, than the second column of the first matrix is multiplied with the second column of the second matrix, etc.
Simple as that.
P.S.
You can not have 0 data in your matrix becose 0^0 is error.
But you can put instead of 0, 1^-9 .There will be no error and on the other hand you will have the number very close to zero.
ZTC
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