Sorry mate, I was sure I read that as
=RANDBETWEEN(3,1)
Need to change eyes![]()
Sorry mate, I was sure I read that as
=RANDBETWEEN(3,1)
Need to change eyes![]()
oldchippy
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Didn't expect so many solutions but much appreciated. Good to know for future reference.
I ended up using =INT(8*RAND()) + 3 and/or =round((rand() *7 + 3),2) . Could not use the Randbetween function as my company is still using Office 2000.
Thanks for comments.
If you use ROUND, the end-point numbers will occur with half the likelihood of the interior numbers.
To see a quick example, copy =ROUND(3 * RAND(), 0) down 600 rows. On average, you'll see 100 0's, 200 1's, 200 2's, and 100 3's.
Entia non sunt multiplicanda sine necessitate
Good point. Thanks for the tip...another one I can file away for future reference.
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