Searching right to left for a differing value

Hi everyone.
Given: A row with either positive real numbers or zero in each cell, i.e,

0 0 459.11 0 0 0 11 0 0 11198.1 0 0 0

I need to scan the row right to left, and return one of the following:

The number of zeros before the first non-zero value appears
The address of the last zero cell encountered or the first non-zero cell

The values are not arranged in any sort of order, and cannot be reordered, which killed my attempt at using an OFFSET/MATCH combination.

I think I could do this by simply parsing a text string, but I haven't figured out a way to automatically concatenate the entire row.

Oh, and if it's any help, the row will *always* be the same length.

My next step is VBA, but I've never worked with it, and I'd really like to avoid it if I can.

Thanks for any and all hints you can offer!

Assuming your data is in A1:M1

To give the number of zeroes before the first non-zero value appears (3, I believe in your example above)

=COLUMNS(A1:M1)-MATCH(2,1/(A1:M1))

and the address of the first non-zero value (from the right)

=CELL("address",INDEX(A1:M1,MATCH(2,1/(A1:M1))))

both formulas need to be "array entered" i.e. confirmed with CTRL+SHIFT+ENTER so that curly braces appear around the formula in the formula bar

Thank you very much for your help. The project got back-burnered for a while, so I am only now getting back to it. Sorry for not acknowledging your help earlier!