Calculating median with several criteria

Pls try this formula

Formula:

=MEDIAN(IF((B:B<=35)*(A:A>=--"2017/1/1")*(A:A<=--"2017/12/31"),C:C))

Try this

=MEDIAN(IF($B:$B<=35,IF($A:$A>=DATE(2017,1,1),IF($A:$A<=DATE(2017,12,31),$C:$C))))

Or:

=MEDIAN(IF($B:$B<=35,IF(YEAR($A:$A)=2017,$C:$C)))

This worked great.
How come though when I remove the age it does not work?

WORKS: MEDIAN(IF($B:$B<=35,IF(YEAR($A:$A)=2017,$C:$C)))
DOES NOT WORK: MEDIAN(IF(YEAR($A:$A)=2017,$C:$C)))

This worked great.
How come though when I remove the age it does not work?

WORKS: MEDIAN(IF($B:$B<=35,IF(YEAR($A:$A)=2017,$C:$C)))
DOES NOT WORK: MEDIAN(IF(YEAR($A:$A)=2017,$C:$C)))

Originally Posted by jatzbiscuits

this worked great.
How come though when i remove the age it does not work?

Works: Median(if($b:$b<=35,if(year($a:$a)=2017,$c:$c)))
does not work: Median(if(year($a:$a)=2017,$c:$c)))

Formula:

=median(if(isnumber(a:a),(year(a:a)=2017)*c:c))

@Jatzbiscuits You're Welcome. Glad to help . Thank You for the feedback.


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E2=aggregate(16,6,c2:c20/(year(a2:a20)=2017)/(b2:b20<=35.1),0.5)

with aggregate works with enter

Ans. Post#6

Formula:

=aggregate(16,6,c:c/(year(a:a)=2017),0.5)