b c 2 acw% 3 0-13-15 13% 4 0-27-11 27% 5 0-0-0 0%
b c 2 acw% 3 0-13-15 =(--substitute(mid(b3,search("-*?*-",b3),3),"-",""))/100 4 0-27-11 =(--substitute(mid(b4,search("-*?*-",b4),3),"-",""))/100 5 0-0-0 =(--substitute(mid(b5,search("-*?*-",b5),3),"-",""))/100
or if you predict middle number >99% (3 digits) use:
Formula:
=(--TRIM(MID(SUBSTITUTE(B3, "-", REPT(" ", 99)),100,99)))/100
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