The aggregate mean, E[X], is simple: dot product of sample mean and sample size arrays divided by sum of sample size array.
Formula:
=SUMPRODUCT(B2:B26,C2:C26)/B28
Aggregate standard deviation is more involved. Assuming each sample's variance were based on dividing by the sample's N-1 rather than N, I believe it should be
SD[Xs]2 = Var[Xs] = sum((Xsi - E[Xs])2) / (Ns - 1)
(Ns - 1) SD[Xs]2 = sum((Xsi - E[Xs])2) = sum(Xsi2) - Ns E[Xs]2
sum(Xsi2) = (Ns - 1) SD[Xs]2 + Ns E[Xs]2
Var[X] = sums(sum(Xsi2)) / sums(Ns) - E[X]2
Formula:
=SQRT((SUMPRODUCT(B2:B26-1,D2:D26^2)+SUMPRODUCT(B2:B26,C2:C26^2))/B28-C28^2)
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