Transpose column against repeated cells

I don't understand why you are using the old .xls format with Excel 2013. I have provided a solution using PowerQuery:

M Code:

let
    Source = Excel.CurrentWorkbook(){[Name="Table1"]}[Content],
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"CONSIGNEE", type text}, {"AC#", Int64.Type}, {"WR#", Int64.Type}, {"DESCRIPTION", type text}, {"LBS", Int64.Type}, {"SHIPPER", type text}, {"PHONE", type text}, {"EMAIL", type text}, {"ADDRESS", type text}, {"VALUE", type number}, {"%", Int64.Type}, {"FREIGHT", type number}, {"FUEL", type number}, {"CUSTOMS & DUTY", type number}, {"VAT", type number}, {"ONLINE PURCHASE TAX", type number}, {"INSURANCE FEE", type number}, {"BROKERAGE FEE", type number}, {"TOTAL", type number}}),
    #"Unpivoted Other Columns" = Table.UnpivotOtherColumns(#"Changed Type", {"CONSIGNEE", "AC#", "WR#", "DESCRIPTION", "LBS", "SHIPPER", "PHONE", "EMAIL", "ADDRESS"}, "Attribute", "Value.1"),
    #"Filtered Rows" = Table.SelectRows(#"Unpivoted Other Columns", each ([Attribute] <> "%" and [Attribute] <> "TOTAL" and [Attribute] <> "VALUE"))
in
    #"Filtered Rows"

3 Formulae.

A2, copied across and dnown:
=IFERROR(INDEX(Main!$A:$I,AGGREGATE(15,6,ROW(Main!$A$2:$A$15)/(Main!$A$2:$A$15<>""),1+INT((ROWS(A$2:A2)-1)/7)),MATCH(A$1,Main!$A$1:$I$1,0)),"")

J2, copied down:
=IF($A2="","",INDEX(Main!$L$1:$R$1,,1+MOD((ROWS(J$2:J2)-1),7)))

K2, copied down:
=IF($A2="","",INDEX(Main!$L$2:$R$15,1+INT((ROWS(K$2:K2)-1)/7),1+MOD((ROWS(K$2:K2)-1),7)))

adjust the bits in red to give yourself some spare capacity... saved as an xlsx. Why are you still using the obsolete .xls format???

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You're welcome.