Hi,

what is the 'real' formula of norm.s.dist(x,TRUE) ?

on the microsoft help page I can only find the formula for norm.s.dist(WRONG)
The given example there: =NORM.S.DIST(1.333333,TRUE) Example: 0.908788726 (description: Normal cumulative distribution function at 1.333333)

Could someone please let me know how I can calculate the 0,908.. on my own?

Thanks in advance,