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Equation giving unexpected results

  1. #1
    Mike K
    Guest

    Equation giving unexpected results

    Oh Wise Ones,

    I have a chart that gave me the equation
    below. When I tried to solve for x, I keep getting
    unexpected results. What am I doing wrong?

    B5=1.1563 inches, B8=.76lbs
    D5=.6875 inches, D8=.34lbs
    When I solve for y (courtesy algebrahelp.com) I don't get
    the correct results. From the cell relationships above if
    C5 contains 1.1250 inches, it should yield a lbs result
    between .76 and .34. I get: x = 1.066552901

    Trend gives me: y = -0.4688x + 1.625


    Mike

    Simplifying
    1.125 = -0.4688x + 1.625

    Reorder the terms:
    1.125 = 1.625 + -0.4688x

    Solving
    1.125 = 1.625 + -0.4688x

    Solving for variable 'x'.

    1.125 + 0.4688x = 1.625 + -0.4688x + 0.4688x

    1.125 + 0.4688x = 1.625 + 0.0000
    1.125 + 0.4688x = 1.625

    1.125 + -1.125 + 0.4688x = 1.625 + -1.125

    0.000 + 0.4688x = 1.625 + -1.125
    0.4688x = 1.625 + -1.125

    1.625 + -1.125 = 0.5
    0.4688x = 0.5

    x = 1.066552901








  2. #2
    Jon Peltier
    Guest

    Re: Equation giving unexpected results

    Mike -

    Two points:

    1. Make sure you're getting lots of significant digits in the equation.
    Double click the label containing the equation, and on the Number tab,
    choose a scientific or number with lots of decimal digits.

    2. Make sure you've created an XY Scatter chart, not a Line chart. The
    line chart uses 1, 2, 3 for its X calculations, while the scatter chart
    uses the actual numerical X values.

    - Jon
    -------
    Jon Peltier, Microsoft Excel MVP
    Peltier Technical Services
    Tutorials and Custom Solutions
    http://PeltierTech.com/
    _______

    Mike K wrote:

    > Oh Wise Ones,
    >
    > I have a chart that gave me the equation
    > below. When I tried to solve for x, I keep getting
    > unexpected results. What am I doing wrong?
    >
    > B5=1.1563 inches, B8=.76lbs
    > D5=.6875 inches, D8=.34lbs
    > When I solve for y (courtesy algebrahelp.com) I don't get
    > the correct results. From the cell relationships above if
    > C5 contains 1.1250 inches, it should yield a lbs result
    > between .76 and .34. I get: x = 1.066552901
    >
    > Trend gives me: y = -0.4688x + 1.625
    >
    >
    > Mike
    >
    > Simplifying
    > 1.125 = -0.4688x + 1.625
    >
    > Reorder the terms:
    > 1.125 = 1.625 + -0.4688x
    >
    > Solving
    > 1.125 = 1.625 + -0.4688x
    >
    > Solving for variable 'x'.
    >
    > 1.125 + 0.4688x = 1.625 + -0.4688x + 0.4688x
    >
    > 1.125 + 0.4688x = 1.625 + 0.0000
    > 1.125 + 0.4688x = 1.625
    >
    > 1.125 + -1.125 + 0.4688x = 1.625 + -1.125
    >
    > 0.000 + 0.4688x = 1.625 + -1.125
    > 0.4688x = 1.625 + -1.125
    >
    > 1.625 + -1.125 = 0.5
    > 0.4688x = 0.5
    >
    > x = 1.066552901
    >
    >
    >
    >
    >
    >
    >


  3. #3
    Tushar Mehta
    Guest

    Re: Equation giving unexpected results

    In addition to Jon's suggestions, consider using the LINEST function to
    get the regression coefficients directly in worksheet cells.

    --
    Regards,

    Tushar Mehta
    www.tushar-mehta.com
    Excel, PowerPoint, and VBA add-ins, tutorials
    Custom MS Office productivity solutions

    In article <0a5901c503ee$df1a26e0$a401280a@phx.gbl>,
    anonymous@discussions.microsoft.com says...
    > Oh Wise Ones,
    >
    > I have a chart that gave me the equation
    > below. When I tried to solve for x, I keep getting
    > unexpected results. What am I doing wrong?
    >
    > B5=1.1563 inches, B8=.76lbs
    > D5=.6875 inches, D8=.34lbs
    > When I solve for y (courtesy algebrahelp.com) I don't get
    > the correct results. From the cell relationships above if
    > C5 contains 1.1250 inches, it should yield a lbs result
    > between .76 and .34. I get: x = 1.066552901
    >
    > Trend gives me: y = -0.4688x + 1.625
    >
    >
    > Mike
    >
    > Simplifying
    > 1.125 = -0.4688x + 1.625
    >
    > Reorder the terms:
    > 1.125 = 1.625 + -0.4688x
    >
    > Solving
    > 1.125 = 1.625 + -0.4688x
    >
    > Solving for variable 'x'.
    >
    > 1.125 + 0.4688x = 1.625 + -0.4688x + 0.4688x
    >
    > 1.125 + 0.4688x = 1.625 + 0.0000
    > 1.125 + 0.4688x = 1.625
    >
    > 1.125 + -1.125 + 0.4688x = 1.625 + -1.125
    >
    > 0.000 + 0.4688x = 1.625 + -1.125
    > 0.4688x = 1.625 + -1.125
    >
    > 1.625 + -1.125 = 0.5
    > 0.4688x = 0.5
    >
    > x = 1.066552901
    >
    >
    >
    >
    >
    >
    >
    >


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